The energy carried by a single photon of frequency f is given by: [tex]E=hf[/tex] where [tex]h=6.6 \cdot 10^{-34} m^2 kg s^{-1}[/tex] is the Planck constant. In our problem, the frequency of the photon is [tex]f=7.15 \cdot 10^{14}Hz[/tex], and by using these numbers we can find the energy of the photon: [tex]E=(6.6\cdot 10^{-34}m^2 kg s^{-1})(7.15 \cdot 10^{14}Hz)=4.7 \cdot 10^{-19}J[/tex]
