Respuesta :

Apocrophon
The two monomial have the same variable to the same power so you just subtract the 14 from 10:

[tex]10y^{10}-14y^{10}\\\\(10-14)y^{10}\\\\-4y^{10}[/tex]

Answer:

The required solution is [tex]-4y^{10}[/tex].

Step-by-step explanation:

The given expression is

[tex]10y^{10}-14y^{10}[/tex]

Take out the common factor [tex]y^{10}[/tex] from both terms.

[tex]y^{10}(10-14)[/tex]

[tex]y^{10}(-4)[/tex]

[tex]-4y^{10}[/tex]

Therefore the required solution is [tex]-4y^{10}[/tex].