How many moles are in 1.50 g of ethylamine, ch3ch2nh2?

mass = mass/molar mass of ch3ch2nh2
the molar mass of CH3CH2NH2 = 12 +(1x3)+12+(1 x2)+14+(1x2) =45 g/mol

moles is therefore = 1.50g /45g/mol = 0.033 moles

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kobenhavn kobenhavn · Answer 2 · 2019-02-24T15:56:09+01:00

Answer: 0.03 moles

Explanation:

To calculate the moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\textMolar mass}}[/tex] ....(1)

For ethyl amine [tex]CH_3CH_2NH_2[/tex]

Mass of ethyl amine [tex]CH_3CH_2NH_2[/tex]= 1.50 g

Molar mass of ethyl amine [tex]CH_3CH_2NH_2[/tex]= 45 g/mol

Putting values in above equation, we get:

[tex]\text{Moles of ethyl amine}=\frac{1.50g}{45g/mol}=0.03moles[/tex]