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A 41.0 ml barium hydroxide solution of molarity 3.41 m is diluted with water to form 279 ml of solution. calculate the molarity of the solution

Respuesta :

Using the dilution equation
M1V1=M2V2
M1 is the initial molarity, V1 the initial volume, while V2 is the final volume after dilution, while M2 is the molarity after dilution.
Hence
 41 × 3.41 = 279 × M2
M2 = (41 ×3.41)/279
      = 0.5011 M
Therefore; the molarity after dilution is 0.5011 M

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