Alright, lets get started.
[tex] y = x^2 + 14 x - 40 [/tex]
For making complete square, we will add and subtract 49 in this
[tex] y = x^2 + 14 x - 40 + 49 - 49 [/tex]
[tex] y = x^2 + 14 x + 49 -40 - 49 [/tex]
[tex] y = (x+7)^2 - 40 - 49 [/tex]
[tex] y = (x+7)^2 - 89 [/tex]
Comparing the standard equation of parabola
[tex] y = a (x-h)^2 + k [/tex] where (h,k) are vertex
So, comparing the equation with standard one, h, k would be = (-7 , -89)
So, the vertex are (-7 , -89) : Answer
Hope it will help :)
