The perimeter of a rectangular garden is 100 feet​ (ft). the area of the rectangular garden area is 600 ft2. find the length and width of the garden. let the length of the garden be the shorter​ side, of necessary.
let the length be x and the width be y: Area=x*y=600 thus x=600/y
Perimeter=2(L+W) 100=2(x+y) substituting the value of x we obtain: 100=2(600/y+y) solving for y we shall have: 50=600/y+y 50y=600+y^2 thus y^2-50y+600=0 solving the quadratic we obtain: y=20 or y=30 thus the length=30 ft and the width=20 ft